x^2+x(6-2x)=(x-2)(x+2)

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Solution for x^2+x(6-2x)=(x-2)(x+2) equation: 



x^2+x(6-2x)=(x-2)(x+2)

We move all terms to the left:

x^2+x(6-2x)-((x-2)(x+2))=0

We add all the numbers together, and all the variables

x^2+x(-2x+6)-((x-2)(x+2))=0

We use the square of the difference formula

x^2+x^2+x(-2x+6)+4=0

We multiply parentheses

x^2+x^2-2x^2+6x+4=0

We add all the numbers together, and all the variables

6x+4=0

We move all terms containing x to the left, all other terms to the right

6x=-4

x=-4/6

x=-2/3

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